Re: Chimps outsmart college students

"Wayne Throop" <throopw@[EMAIL PROTECTED]
> wrote in message 
news:1196967070@[EMAIL PROTECTED]
>: "Ken from Chicago" <kwicker1b_nospam@[EMAIL PROTECTED]
>
> : Ask anyone with a cell phone the phone numbers to their friends.
>
> My spouse's phone number is options-contacts-find-send...
> that's what I type anyways (she sorts to the head of the list).
> (well, actually, more often, her number is send-send)
> (my use of speed dialing is very very crude)

Or "redial".

> And my phone number is (um, options-one-four
> aka options-contacts-myphone#) yeah, that's it.
> I *might* be able to remember the actual digits on a
> good clear day with a strong tailwind.
>
> Good thing it's got a calculator.  Can't do arithmetic in my head
> anymore, either.  And reminders, it's got reminders...  *amongst* it's
> divers features...

Microsoft Word and later Google majorly undermined my spelling confidence.

Fortunately I find math soothing and relaxing.

> Disgustingly enough, I can remember the land-line phone number
> of my families former house, where I haven't lived for more than 30
years.
> Now *there's* some neurons I'm apparently never getting back.
>
>
> Wayne Throop   throopw@[EMAIL PROTECTED]
   http://sheol.org/throopw

h = h' + v't - (g)(t)(t+1sec)(1/2)

h = 0: h = 0 = h' + v't - (g/2)(t)(t+1sec) = h' + v't - 
(16ft/sec^2)(t)(t+1sec)
0 = h' + v't - (16ft/sec^2)(t^2) - (16ft/sec)(t)
0 = h' + v't - (16ft/sec)(t) - (16ft/sec^2)(t^2)
0 = h' + (v' - 16ft/sec)(t) - (16ft/sec^2)(t^2)
(16ft/sec^2)(t^2) - (v' - 16ft/sec)(t) = h'
(16ft)(t^2) - (v'sec^2 - 16ftsec)(t) = h'sec^2
t^2 - [(v')(sec^2)/(16ft) - sec](t) = (h')(sec^2)
t^2 - [(v')(sec)/(16ft) - 1](sec)(t) = (h')(sec^2)
t^2 - [(v')(sec)/(16ft) - 1](sec/2) + {[(v')(sec)/(16ft) - 1](sec/2)}^2
 = {[(v')(sec)/(16ft) - 1](sec/2)}^2 + (h')(sec^2)
{t - [(v')(sec)/(16ft) - 1](sec/2)}^2
 = {[(v')(sec)/(16ft) - 1](sec/2)}^2 + (h')(sec^2)
t - [(v')(sec)/(16ft) - 1](sec/2)
 = sqrt<{[(v')(sec)/(16ft) - 1](sec/2)}^2 + (h')(sec^2)>

So that:

t = [(v')(sec)/(16ft) - 1](sec/2)
 + sqrt<{[(v')(sec)/(16ft) - 1](sec/2)}^2 + (h')(sec^2)>

Where:
h' = initial height in feet
v' = initial velocity in feet/sec
t = time in seconds elapsed before one hits the ground (where h = 0).

-- Mathematical Ken from Chicago