Re: What would the end velocity be if...?

On Feb 19, 4:31=A0pm, Erik Max Francis <m...@[EMAIL PROTECTED]
> wrote:
> STJensen wrote:
> > Someone is placed in a capsule of an electro-magnetic repulsion
> > accelerator in the weightless vacuum of space and accelerated along
> > its entire length. =A0If the g force the person feels is 2g (32 ft/s-
> > squared x 2) during the entire time along the accelerator and the
> > accelerator is 60,000 miles long, how fast would the person be
> > traveling when they leave the accelerator and how long would their run
> > on the accelerator last?
>
> For straight-line, constant acceleration, starting from rest, with no
> other forces acting, the equations are:
>
> =A0 =A0 =A0 =A0 s =3D (1/2) a t^2
>
> =A0 =A0 =A0 =A0 v =3D a t
>
> where t is the elapsed time, v is the accumulated speed, s is the
> accumulated distance, and a is the acceleration.
>
> Solving one for t and substituting (since you're not concerned with the
> total time), you get
>
> =A0 =A0 =A0 =A0 v^2 =3D 2 a s.
>
> Now plug in numbers and experiment.
>
> > If I understand g forces in the weightless of space, the person/object
> > has to at a constant rate of acceleration to so experience the desired
> > g force. =A0The moment their velocity remains the same, they return to
> > their weightless existence. =A0Thus when the person/machine-part
finally=

> > leaves the 60,000-mile long accelerator, they will return to a
> > weightless existence.
>
> Yes.
>
> --
> Erik Max Francis && m...@[EMAIL PROTECTED]
 &&http://www.alcyone.com/max/
> =A0 San Jose, CA, USA && 37 18 N 121 57 W && AIM, Y!M erikmaxfrancis
> =A0 =A0All delays are dangerous in war.
> =A0 =A0 -- John Dryden, 1631-1700

How do you 'square' time...?