Re: What would the end velocity be if...?

On Feb 22, 9:29=A0am, Erik Max Francis <m...@[EMAIL PROTECTED]
> wrote:
> finite guy wrote:
> > Regarding rocket.html
> > A photon is an 'object'.
> > It's mass=3D0 but it has momentum...
> > E=3Dm*c^2 but a photon has energy...
> > Is this not incongruent?
>
> Well, photons can't undergo constant acceleration due to rocket thrust,
> so that's really relevant to the equations James was just talking about.
>
> The answer to your question is that there is no problem with photons
> have no mass but having momentum and energy because the most general
> equation in special relativity relating energy, momentum, and mass is
>
> =A0 =A0 =A0 =A0 E^2 =3D m^2 c^4 + p^2 c^2.
>
> For a particle at rest (p =3D 0), this decays to E =3D m c^2, the more
> familiar popularized Einstein equation. =A0For a massless particle like
a
> photon (m =3D 0), this decays to E =3D p c, the equation relating a
luxon'=
s
> energy to its momentum.
>
> --
> Erik Max Francis && m...@[EMAIL PROTECTED]
 &&http://www.alcyone.com/max/
> =A0 San Jose, CA, USA && 37 18 N 121 57 W && AIM, Y!M erikmaxfrancis
> =A0 =A0Do we ask what profit the little bird hopes for in singing?
> =A0 =A0 -- Johannes Kepler, 1571-1630

A particle is 'at rest' at delta time =3D 0...
How do you successfully divide by zero?