Re: What would the end velocity be if...?

finite guy wrote:
> On Feb 22, 10:13 am, Erik Max Francis <m...@[EMAIL PROTECTED]
> wrote:
>> finite guy wrote:
>>> On Feb 22, 9:29 am, Erik Max Francis <m...@[EMAIL PROTECTED]
> wrote:
>>>> finite guy wrote:
>>>>> Regarding rocket.html
>>>>> A photon is an 'object'.
>>>>> It's mass=0 but it has momentum...
>>>>> E=m*c^2 but a photon has energy...
>>>>> Is this not incongruent?
>>>> Well, photons can't undergo constant acceleration due to rocket
thrust,
>>>> so that's really relevant to the equations James was just talking
about.
>>>> The answer to your question is that there is no problem with photons
>>>> have no mass but having momentum and energy because the most general
>>>> equation in special relativity relating energy, momentum, and mass is
>>>>         E^2 = m^2 c^4 + p^2 c^2.
>>>> For a particle at rest (p = 0), this decays to E = m c^2, the more
>>>> familiar popularized Einstein equation.  For a massless particle like
a
>>>> photon (m = 0), this decays to E = p c, the equation relating a
luxon's
>>>> energy to its momentum.
>>> A particle is 'at rest' at delta time = 0...
>>> How do you successfully divide by zero?
>> No division by zero is taking place in anything I wrote, so I don't
know
>> what you're talking about.
>>
>> If you're asking how to consider instantaneously changing variables,
>> then the answer is differential calculus.
> 
> I'm asking you to consider how a photon moves from here to there.

You were asking about particles at rest, which can't include photons, so 
I don't know what you're asking.

-- 
Erik Max Francis && max@[EMAIL PROTECTED]
 && http://www.alcyone.com/max/
  San Jose, CA, USA && 37 18 N 121 57 W && AIM, Y!M erikmaxfrancis
   There is no easy way from the Earth to the stars.
    -- Seneca, ca. 1st C.