Orbital towers again, I'm afraid...
If we assume a standard construction for a tower, with a tether
dirtside, an asteroidal counterweight at the far end, and a waystation
at LEO, am I right in assuming that the waystation is actually in a
orbit too slow for its particular value of r?
This being the case, the waystation will have gravity (towards Earth)
proportional to r^2 minus that due to its rotational v? And not in
freefall as I've described in the first draft?
I have a feeling of startling stupidity mediated only by the immense
relief of having spotted it now, before it got any further.
Simon Morden
--
Visit the *all new* Book of Morden (www.bookofmorden.co.uk)
"I haven't had that much fun with a novel for a while." - Bookbag
The Lost Art - from David Fickling Books


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